-12m^2+1m+20=0

Solution for -12m^2+1m+20=0 equation:

-12m^2+1m+20=0

We add all the numbers together, and all the variables

-12m^2+m+20=0

a = -12; b = 1; c = +20;
Δ = b2-4ac
Δ = 12-4·(-12)·20
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-31}{2*-12}=\frac{-32}{-24}
=1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+31}{2*-12}=\frac{30}{-24}
=-1+1/4
$